Search found 28 matches
- Sun Dec 02, 2012 5:08 am
- Forum: Common Lisp
- Topic: Help me on Tokinzer
- Replies: 2
- Views: 6662
Re: Help me on Tokinzer
As far as I know, there is no ready-to-use splitting function in the cl standard. However you can use the cl-split-sequence library, available through quicklisp . Assuming quicklisp is installed, CL-USER> (ql:quickload :split-sequence) To load "split-sequence": Load 1 ASDF system: split-se...
- Sat Dec 01, 2012 12:39 pm
- Forum: Common Lisp
- Topic: what is a list designator?
- Replies: 2
- Views: 7526
Re: what is a list designator?
Thanks, I looked at the section 1.4.1.5 on designators, but the info is indeed in the glossary.
- Sat Dec 01, 2012 11:04 am
- Forum: Common Lisp
- Topic: what is a list designator?
- Replies: 2
- Views: 7526
what is a list designator?
Hi, The hyperdoc for the case macro talks about list designators. But what is a list designator? Reading the definition in the hyperspec did not help. I guess I understand what is a string designator: a keyword, a symbol or a string. But a list designator? The case examples seem to indicate that eve...
- Sun Nov 18, 2012 10:37 am
- Forum: Common Lisp
- Topic: iterative copy of a tree
- Replies: 0
- Views: 8170
iterative copy of a tree
Recently, the recursive code for the copy-tree function in sbcl was rewritten so as to prevent stackoverflow on long lists. This prompted me to write an iterative version, one-pass, no stack, no unnecessary consing, version of copy-tree in common-lisp, working with nested, perhaps dotted, lists. The...
- Mon Nov 12, 2012 4:01 am
- Forum: Common Lisp
- Topic: Replacing a function in an expression
- Replies: 20
- Views: 48031
Re: Replacing a function in an expression
@Paul I found that the pcl code walker ships with sbcl. A bit of googling even dug up a thread showing how to use it in my particular case. Many thanks to all the people that answered my question. I now understand a lot more about code transformation in common lisp, and I will try to build up my own...
- Sun Nov 11, 2012 2:39 pm
- Forum: Common Lisp
- Topic: Replacing a function in an expression
- Replies: 20
- Views: 48031
Re: Replacing a function in an expression
@ Paul Are there implementation independant common lisp code walkers? A quick google search suggests that there are a few edge cases which are not so easy to handle. I am using sbcl, so maybe there is a way to leverage some sbcl compatible code walker to deal with code substitution, without having t...
- Sun Nov 11, 2012 2:32 pm
- Forum: Common Lisp
- Topic: Replacing a function in an expression
- Replies: 20
- Views: 48031
Re: Replacing a function in an expression
Thanks for the answer, Goheeca, still I fail to see how it addresses the question.
macrolet does expansion then evaluation, doesn't it?
I want to transform the source code without evaluating it, in order to modify programmatically source files.
macrolet does expansion then evaluation, doesn't it?
I want to transform the source code without evaluating it, in order to modify programmatically source files.
- Sun Nov 11, 2012 2:02 pm
- Forum: Common Lisp
- Topic: Replacing a function in an expression
- Replies: 20
- Views: 48031
Re: Replacing a function in an expression
Unfortunately, the code provided by Goheeca does not work for me. I never used the macrolet operator before, maybe someone can point to a beginner friendly introduction to macrolet? I have used macros before, but I don't understand the macrolet section of the hyperspec at the moment. CL-USER> (defun...
- Sun Nov 11, 2012 3:34 am
- Forum: Common Lisp
- Topic: Replacing a function in an expression
- Replies: 20
- Views: 48031
Replacing a function in an expression
I am trying to understand the "code-is-data" motto in common lisp. So I have an expression and I want to replace all occurrences of the function list by my-list, as follows. (defparameter *expr* '(let ((list (quote (1 2 3)))) ;; comment list (append list (list 4 5 'list "list, 'list, ...
- Fri Nov 09, 2012 9:34 am
- Forum: Common Lisp
- Topic: format with two lists
- Replies: 1
- Views: 5830
format with two lists
hi,
is there a format directive that loops over two lists, as follows?
I know that I can map format on the two lists. My goal here
is to understand the format directives a bit better.
is there a format directive that loops over two lists, as follows?
Code: Select all
(format "..." (list 1 2 3) (list 'a 'b 'c ))
=> 1 'a
2 'b
3 'c
is to understand the format directives a bit better.