LispForum

I see. Well, rather confusing on the part of the standard. I don't see the point in in this behaviour, but I guess this is the way the satandard goes.

Thanks a lot for your posts.

Pep.

So, if I understand well, that means that when the bit pattern and the type are the same, then EQ returns T, even if the bit pattern represents a number and not an address. However, that is in contradiction with Ramarren's post, as he says: Since Common Lisp is call-by-value (even if the majority of...

Thanks for the reply, it makes me understand how it works. As for the piece of code: (setq a 5) (setq b 5) (eq a b) T It makes sense that it returns true if: 1. This particular implementation stores references, and not the pattern '5'. 2. The implementation is using the very same memory address for ...

I've just started learning lisp, and I've encountered my first doubt: it's regarding EQ. I undertand that, as lisp implementations have the freedom to make copies of numbers and characters at any time, you cannot assume, for instance, that (eq 3 3) will be true, as yo cannot assume the first object ...