LispForum

Hello all! Maybe this question is very easy, but I can't find the solution. the output of (caadr (cadr ’(a ’(b (c))))) is b if we'll execute the second part of the expression: (cadr ’(a ’(b (c)))), the output will be ’(b (c)) but, the output of (caadr ’(b (c))) is c, not b! Why does it h...