i made it!!!
thanks....
regards
Search found 4 matches
- Tue Mar 16, 2010 11:50 am
- Forum: Common Lisp
- Topic: Divide arc by measurin leight and radius
- Replies: 6
- Views: 6367
- Mon Mar 15, 2010 12:12 pm
- Forum: Common Lisp
- Topic: Divide arc by measurin leight and radius
- Replies: 6
- Views: 6367
Re: Divide arc by measurin leight and radius
OK, I get X from arc that I selected, but how to round result (x=7.2545) to first bigger integer?
and than how to make code to divide that selected arc to X segments?
THANKS....
and than how to make code to divide that selected arc to X segments?
THANKS....
- Sun Mar 14, 2010 1:03 pm
- Forum: Common Lisp
- Topic: Divide arc by measurin leight and radius
- Replies: 6
- Views: 6367
Re: Divide arc by measurin leight and radius
could you be more precisely? please...
- Thu Mar 11, 2010 4:57 pm
- Forum: Common Lisp
- Topic: Divide arc by measurin leight and radius
- Replies: 6
- Views: 6367
Divide arc by measurin leight and radius
I need lisp that can divide any arc on segments by formula : X= L / 2*sqrt((R^2-(R-0.2)^2);
X - number of segments (first integer bigger than result of formula)
L - arc leight
R - radius of arc
X - number of segments (first integer bigger than result of formula)
L - arc leight
R - radius of arc